A balloon has a volume of 240 mL at room temperature (25°C or 298 K). What temperature would you have to heat or cool the balloon to in order to change its volume to 360 mL (Answer in Kelvin)?
please write out the formula and how you solved this so I can see what Im doing wrong
(V1/T1) = (V2/T2)
Post your work if you still have questions.
To solve this problem, we can use the ideal gas law equation, which states:
PV = nRT
Where:
P is the pressure of the gas,
V is the volume of the gas,
n is the number of moles of gas,
R is the ideal gas constant,
T is the temperature of the gas in Kelvin.
To find the temperature at which the volume changes from 240 mL to 360 mL, we can set up the equation as follows:
P1V1 / T1 = P2V2 / T2
Where:
P1 is the initial pressure (which we can assume remains constant),
V1 is the initial volume,
T1 is the initial temperature,
P2 is the final pressure (which we can assume remains constant),
V2 is the final volume,
T2 is the final temperature.
Since the pressure is constant in this problem, we can ignore the P1 and P2 terms:
V1 / T1 = V2 / T2
Now, let's plug in the given values:
V1 = 240 mL = 0.240 L
T1 = 298 K
V2 = 360 mL = 0.360 L
Rearranging the equation to solve for T2, we get:
T2 = (V2 / V1) * T1
Substituting the given values:
T2 = (0.360 L / 0.240 L) * 298 K
Simplifying:
T2 = 1.5 * 298 K
T2 ≈ 447 K
Therefore, you would need to heat or cool the balloon to a temperature of approximately 447 Kelvin in order to change its volume from 240 mL to 360 mL.