# physical

posted by john

staring from rest, a 3.5 kg object is acted upon by an unbalanced force and acquires a speed of 14.0 m/s after moving a distance of 35 m. find (a) the acceleration of the object, (b) the unbalanced force acting on the object, and (c) the time it takes for the object to attain a speed of 14.0 m/s

1. Scott

starting from rest (0 m/s) means that the average speed is 7 m/s

so it takes 5 s to go 35 m

acceleration = velocity / time = 14 / 5

force = mass * accel = 3.5 * 14/5

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