CH3COOH(aq) + NaOH(aq) → H2O(l) + NaCH3COO(aq)?
Is this a double displacement reaction and a decomposition reaction?
Double displacement reaction
its two reactions
No, it's only ONE reaction. It's a double displacement. You can call it a neutralization, also, since a base is neutralizing an acid.
To determine whether a chemical reaction is a double displacement reaction and a decomposition reaction, let's break it down:
The given equation is: CH3COOH(aq) + NaOH(aq) → H2O(l) + NaCH3COO(aq)
A double displacement reaction involves the exchange of ions between two compounds to form two new compounds. In this reaction, acetic acid (CH3COOH) and sodium hydroxide (NaOH) react to form water (H2O) and sodium acetate (NaCH3COO). Therefore, it can be classified as a double displacement reaction.
A decomposition reaction occurs when a single compound breaks down into two or more simpler substances. In this reaction, acetic acid decomposes into water and sodium acetate. Therefore, it can also be classified as a decomposition reaction.
In conclusion, the given reaction can be classified as both a double displacement reaction and a decomposition reaction.