Darren drew a scale drawing of a shopping center. The scale of the drawing was 5 millimeters = 2 meters. The parking lot is 145 millimeters in the drawing. How wide is the actual parking lot?

To find out the width of the actual parking lot, we need to use the scale given in the problem. The scale tells us that 5 millimeters on the drawing represents 2 meters in real life.

First, we need to set up a proportion to relate the measurement on the drawing to the actual measurement.

Let's assume that the width of the actual parking lot is "x" meters. Based on the scale, we can set up a proportion as follows:

5 millimeters (on drawing) / 2 meters (actual) = 145 millimeters (on drawing) / x meters (actual)

Now, we can solve for "x" by cross-multiplying:

5 millimeters * x meters = 145 millimeters * 2 meters

5x = 290

Dividing both sides of the equation by 5:

x = 58

So, the width of the actual parking lot is 58 meters.

the scale factor is ... 2 m / 5 mm

multiply the dimension by the scale factor