A new element has been discovered and you are on the task force to determine where this new element will be placed on the periodic table with its known properties.
Using the model of the periodic table and its periodic patterns, analyze the data of the newly discovered element and make a claim to predict where the element would be located on the periodic table. Justify your claim with evidence based on your reasoning of the models and the patterns.
Properties of newly discovered element:
-Mass number 304 amu
-Very low ionization energy
-Bonds easily with other elements
-Melting point 50.1 oC
-The smallest electronegativity
- Predicatively the largest atomic radius
-Great metallic character
-Silver in color
Claim: The “new element” is located in group 1, alkali metals, creating a new period, period 8, and is beneath the element francium. This would make the newly discovered element 119.
Evidence: One property of the newly discovered element is that the mass number is 304 a.m.u. The mass number is the total number of protons and neutrons in an atom. The order of increasing atomic number generally corresponds with increasing atomic mass. For example, element 118 is ununennium and the mass number is 294. The “new element” has very low ionization energy. Ionization energy is energy required to remove an electron. In a period, there is an increase in ionization energy when going across. The energy required to remove electrons from alkali metals is very low. On the periodic table, the bottom left to top right is low ionization energy to high ionization energy. The discovered element bonds easily with other elements. The alkali metals bond easily with other elements, since they each have one valence electron. The melting point of the “new element” is 50.1 degrees celsius. The melting point is the amount of energy required to break a bond to change the solid phase of a substance to a liquid. Melting points are varied and don’t usually form a trend across the periodic table, but alkali metals generally have the melting point between the degrees of 179 celsius and 28.5 celsius. Another property of the “new element” is that it’s the smallest electronegativity. Electronegativity is a qualitative property and measures an atom’s tendency to attract and form bonds with electrons. The electronegativity decreases when it is top to bottom in a group. Most smaller electronegativity elements are in group 1. In the current periodic table, the lowest electronegativity value is francium. The discovered element predicatively has the largest atomic radius. The atomic radius on the periodic table decreases from left to right across a period and increases from top to bottom in a group. According to the periodic table chart with atomic radii, it displays that francium has the highest atomic radius and helium has the lowest. The property of the new element has a great metallic character. In group one, alkali metals have many metallic characters, such as, they are shiny, soft, reactive, malleable, ductile, and good conductors of electricity and heat. The last property of the “new element” is that it is silver in color. Alkali metals have different colors, but francium is silver which connects with the new element.
Reasoning: The location for the “new element” is in group one, alkali metals, period 8, an extra period, below the 87th element, francium, and is the atomic number of 119. According to the periodic table, the atomic number and the atomic mass usually correspond with each other while it increases. This proves that the “new element” would be after the element ununennium because the mass number of the element is 294 a.m.u., therefore the “new element” would have the highest atomic mass and it would be after the 118th element. Since the discovered element has low ionization energy, this would place the element near the bottom left of the periodic table because ionization energy increases diagonally to the right. The “new element” bonds easily with other element, in fact, alkali metals also bond easily with other elements. This shows how the untitled element should be placed in group 1, alkali metals because they both can bond easily with other elements. The melting point of the newly discovered element is 50.1 degrees celsius, but melting points don’t generally have a trend across the periodic table, therefore the melting point does not benefit the arrangement of the “new element”. In addition, alkali metals usually have the melting point between the degrees of 179 celsius and 28.5 celsius, for this reason, the undistinguished element can be considered as an alkali metal. The unclassified element has the least amount of electronegativity, thus it is in group 1 with alkali metals because they have less electronegativity. Since the electronegativity decreases while going top to bottom, the nameless element would be under the element francium because that element had the lowest electronegativity in the periodic table. The unidentified element predicatively has the largest atomic radius and since the atomic radius on the periodic table decreases from left to right across a period and increases from top to bottom in a group, the element would be under francium because it had the largest atomic radius before the “new element” was added. The property of the unknown placement element has great metallic character and alkali metals share similar components to metal, hence why the element is in group one with alkali metals. The mysterious element is the color silver, and the element francium is also silver. The appearance of the two elements correlate with each other, which shows that they are related and in the same group. The unnamed element is certainly identified as an alkali metal, in period 8, underneath the element francium, and has the atomic number of 119.
The above response, by Alex W, is fully correct. I would use that. Though do try to paraphrase and don't copy straight. I would not that it is spelled "Chemistry" and not "Chemestry."
Thanks dawg,, clutch
bless up
Very low ionization energy: metal
bonds easily: group 1, or maybe 2
low melting point: group 1
smallest electro: group 1
large atomic rad: in the higher periods
silver in color: luster...metal
So I predict group 1 metal, in higher periods