A car accelerates uniformly from rest to a speed of 70.3 km/h (19.5 m/s) in 14 s. Find the distance the car travels during this time.
the average speed is ... (0 + 19.5) / 2
distance is average speed multiplied by time
To find the distance the car travels during this time, you can use the equation that relates distance, initial velocity, final velocity, and time. The equation for uniformly accelerated motion is:
distance = (initial velocity + final velocity) / 2 * time
Given:
Initial velocity (u) = 0 (as the car starts from rest)
Final velocity (v) = 19.5 m/s
Time (t) = 14 s
Substituting these values into the equation, we have:
distance = (0 + 19.5) / 2 * 14
Now, we can calculate the distance:
distance = 19.5 / 2 * 14
distance = 9.75 * 14
distance = 136.5 meters
Therefore, the car travels a distance of 136.5 meters during this time.