A chemical reaction produces 3.75 L of chlorine gas at STP. How many moles of chlorine are produced by the reaction?
1mol of a gas occupies 22.4 L at STP. So
? mol of a gas occupies 3.75 L at STP?
To find the number of moles of chlorine gas produced by the reaction, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
At STP (Standard Temperature and Pressure), the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K). The ideal gas constant (R) is 0.0821 L∙atm/(mol∙K).
Given that the volume of chlorine gas produced is 3.75 L, we can substitute the given values into the ideal gas law equation:
PV = nRT
n = PV / RT
n = (1 atm) * (3.75 L) / (0.0821 L∙atm/(mol∙K) * 273.15 K)
By performing the calculation, we get:
n = 0.154 moles
Therefore, the chemical reaction produces 0.154 moles of chlorine gas.