Given ray OC is perpendicular to ray OA and <DOA=135 degrees,what would be the measure of <DOC given that <COB=3x-7 and <BOA= -2x+4.

The reason no one has answered this is I have no idea what this looks like. Where is B?

OB is a ray

To find the measure of <DOC, we need to first find the values of x, <COB, and <BOA.

Given that ray OC is perpendicular to ray OA, we know that <COB + <BOA = 90 degrees. We can use this information to find the value of x.

So, <COB + <BOA = 90 degrees
(3x - 7) + (-2x + 4) = 90
Combine like terms: x - 3 = 90
Add 3 to both sides: x = 93

Now that we have the value of x, we can substitute it back into the given equations to find the values of <COB and <BOA.

<COB = 3x - 7
Substituting x = 93: <COB = 3(93) - 7 = 272 degrees

<BOA = -2x + 4
Substituting x = 93: <BOA = -2(93) + 4 = -182 degrees

Now, let's find the measure of <DOC.

Since ray OC is perpendicular to ray OA, <DOC is the supplement of <DOA (180 degrees minus <DOA).

<DOA = 135 degrees
<DOC = 180 - <DOA
<DOC = 180 - 135
<DOC = 45 degrees

Therefore, the measure of <DOC is 45 degrees.