Find three consecutive natural numbers such that the sum of the first and the second is 39 more than the third number.
I dont like the answer
To solve this problem, we need to follow these steps:
Step 1: Define the variables
Let's assume that the three consecutive natural numbers are x, x+1, and x+2.
Step 2: Write the equation
According to the problem statement, the sum of the first two numbers (x and x+1) is 39 more than the third number (x+2). Mathematically, we can express this as:
x + (x+1) = (x+2) + 39
Step 3: Solve the equation
Now, let's solve the equation:
2x + 1 = x + 41
Simplifying, we get:
x = 40
Step 4: Find the three consecutive natural numbers
Using the value of x, we can find the three consecutive natural numbers:
x = 40
x+1 = 41
x+2 = 42
Therefore, the three consecutive natural numbers that satisfy the given condition are 40, 41, and 42.
the consecutive numbers are x, x+1, x+2
you are told that
x + x+1 = 39 + x+2
solve for x and you're almost done.