A sample of nitrogen gas occupies a volume of 20cm3 at 500k and 760mmhg what will it volume be at 860 mmhg and 400k
p1v1/t1 = p2v2/t2
To find the volume of nitrogen gas at a different pressure and temperature, we can use the combined gas law equation:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Where:
P1 = Initial pressure (760 mmHg)
V1 = Initial volume (20 cm^3)
T1 = Initial temperature (500 K)
P2 = Final pressure (860 mmHg)
V2 = Final volume (unknown)
T2 = Final temperature (400 K)
Let's plug in the known values to the equation:
(760 mmHg * 20 cm^3) / (500 K) = (860 mmHg * V2) / (400 K)
Now, we can solve for V2 by rearranging the equation:
(760 mmHg * 20 cm^3 * 400 K) = (860 mmHg * V2 * 500 K)
V2 = (760 mmHg * 20 cm^3 * 400 K) / (860 mmHg * 500 K)
V2 = 29.30 cm^3 (rounded to two decimal places)
Therefore, the final volume of the nitrogen gas will be approximately 29.30 cm^3 when the pressure is 860 mmHg and the temperature is 400 K.