posted by Shania

Assuming a yield of 26.10 percent calculate the actual yield of magnesium nitrate formed from 42.2 g of magnesium and excess copper(ii) nitrate .

  1. Scott

    molar mass Mg ... 24.3 g

    molar mass magnesium nitrate ... 148.3 g

    .261 * (42.2 / 24.3) * 148 g

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