trigonometry(height and distance)
posted by Anamika .
The shadow of a tower when the angle of elevation of the sun is 45 degree is found to be 5m longer when it is 60 degree. Find the height of the tower.

trigonometry(height and distance) 
bobpursley
sin45=h/(d)
sin60=h/(d+5)
h/d=.707
h/(d+5)=.866
d=h*1.414
so
h=(h*1.414+5)*.866
solve for h 
trigonometry(height and distance) 
Scott
the wording of the problem is awkward, but a steeper angle means a shorter shadow
h/(s + 5) = tan(45º) ... h = s + 5
... s = h  5
h / s = tan(60º)
h = h tan(60º)  5 tan(60º)
5 tan(60º) = h [tan(60º)  1) 
trigonometry(height and distance) 
Henry
The distance should be 5m LONGER at 45o.
Tan 45 = h/(d+5).
h = (d+5)*Tan45 = d+5.
Tan60 = h/d.
h = d*Tan60 = 1.73d
d+5 = 1.73d.
d = 6.83 m.
h = d + 5 = 6.83+5 = 11.83 m. 
trigonometry(height and distance) 
bobpursley
I agree.
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