A basketball player throws a ball from a horizontal distance of 10m. The basketball is 3m from tge ground and he releases the ball from a height of 2m from the ground. If he shoots at a 40° angle with the horizontal, at what initial speed must he throw so that a ball goes through the hoop without striking the background?

here is a worked similar problem, use it as a guide

https://www.jiskha.com/display.cgi?id=1360158331

To determine the initial speed at which the basketball player must throw the ball, we can break down the problem into two components: the horizontal and vertical motion.

First, let's consider the vertical component of the motion. The ball is released from a height of 2m and reaches a height of 3m before going through the hoop. The vertical displacement is given by:

Δy = final height - initial height
Δy = 3m - 2m
Δy = 1m

Next, we need to consider the horizontal component of the motion. The distance between the player and the hoop is given as 10m.

Now, let's focus on the angle at which the ball is being shot. We are given that the angle with the horizontal is 40°.

To find the initial speed of the ball, we can use the following kinematic equation for projectile motion:

Δy = viy * t + (1/2) * g * t^2

In this equation:
- Δy is the vertical displacement (1m)
- viy is the initial vertical velocity (unknown)
- t is the total flight time (which we can find, since the horizontal distance is known)
- g is the acceleration due to gravity (9.8m/s^2)

We need to solve for viy. However, we need to first find the total flight time, which is determined by the horizontal motion.

Horizontal distance, d = vi * cos(θ) * t

In this equation:
- d is the horizontal distance (10m)
- vi is the initial velocity (unknown)
- θ is the angle with the horizontal (40°)
- t is the total flight time

Rearrange the equation to solve for t:

t = d / (vi * cos(θ))

Now, substitute this expression for t into the vertical displacement equation:

Δy = viy * (d / (vi * cos(θ))) + (1/2) * g * (d / (vi * cos(θ)))^2

Simplify the equation:

1m = (viy * d) / (vi * cos(θ)) + (1/2) * g * (d^2) / (vi^2 * cos^2(θ))

Now, we have an equation with only one unknown, vi.

To solve for vi, we can use numerical methods or algebraic manipulation. Since the latter can be quite complex, it is often easier to use numerical methods such as trial and error or a calculator that can solve equations like this.

Let's suppose we use trial and error. Start by guessing a value for vi and calculate the right side of the equation. Compare it with the left side of the equation (1m), and adjust the guess until the two values are equal or very close.

Repeat this process until you find the value of vi that satisfies the equation.