Question

Here is a linear inequality to solve:

8x + 8 < 3 (x + 1)

Answer 1

8 x + 8 < 3 ∙ x + 3 ∙ 1

8 x + 8 < 3 x + 3

Subtract 8 to both sides

8 x + 8 - 8 < 3 x + 3 - 8

8 x < 3 x - 5

Subtract 3 x to both sides

8 x - 3 x < 3 x - 5 - 3 x

5 x < - 5

Divide both sides by 5

5 x / 5 < - 5 / 5

x < - 1