The current population of Summerfield is 16,359 people, which is 90% larger than when David moved there. What was the population of Summerfield back then?
I need some help, there's this question on IXL (It's a website that has math problems for you to answer) that I couldn't answer. What I think is we should add 100% and 90% which will be 190%, and then we will divide 1.9 to 16,359. And the answer will be 0.00011614, but the thing is, it doesn't make that much sense to me, does it make sense?
You have it backward. If the original population was x, then
1.9x = 16359
x = 16359/1.9 = 8610
Ohh I see, thank you!
To find the population of Summerfield when David moved there, we can set up an equation using the information given.
Let's assume the population of Summerfield when David moved there is 'x'.
According to the problem, the current population is 90% larger than when David moved there. This means the current population is 100% + 90% = 190% of the past population.
We can express this relationship using the equation:
x + 190% of x = 16,359
To solve this equation, we first convert 190% to decimal form by dividing it by 100: 190/100 = 1.9
Now, we can rewrite the equation:
x + 1.9x = 16,359
Combining the x terms on the left side gives us:
2.9x = 16,359
To isolate x, the unknown population, we divide both sides of the equation by 2.9:
x = 16,359 / 2.9
Evaluating this expression gives us the population of Summerfield when David moved there.