two particles moving along x-axis in the same direction with uniform velocity is 8 metre per second and 4 metre per second initially the first particle is 21 m to the left of the origin and the second one is 7 m to the right of the origin to particle meets from the origin at a distance of
1 st particle
x+21=u¹t
21+x=8t
x=-21+8t....
2 nd particle
x-7=u²t
x=7+4t
equating 1st and 2 nd particles
-21+8t=7+4t
8t-4t=21-7
4t=28
t=28/4 = 7 sec
SUBSTITUTION
x=-21+8t
x=-21+8(7)
x= -21+56=35
(or)
x=7+4t
x=7+4(7)
x=7+28=35
Correct 😀😀
nice solution very easy understanding thanks
Very nice answer bro
Why u took x plus 21=u1t
To find the distance at which the two particles meet from the origin, we can use the concept of relative velocity.
Let's assume that the first particle moves with a velocity of 8 m/s and the second particle moves with a velocity of 4 m/s. Since they are moving in the same direction, the relative velocity between the two particles is the difference between their individual velocities.
Relative Velocity = Velocity of the first particle - Velocity of the second particle
Relative Velocity = 8 m/s - 4 m/s = 4 m/s
Now, let's analyze the initial positions of the particles. The first particle is initially 21 m to the left of the origin, and the second particle is 7 m to the right of the origin.
The time taken by both particles to reach the point of meeting can be calculated by dividing the distance between their initial positions by the relative velocity.
Time = (Distance between initial positions) / (Relative Velocity)
Time = (21 m + 7 m) / (4 m/s)
Time = 28 m / (4 m/s)
Time = 7 seconds
Since both particles have uniform velocity, we can calculate the distance covered by each particle in 7 seconds using the formula: Distance = (Velocity) x (Time)
Distance covered by the first particle = 8 m/s x 7 s = 56 m
Distance covered by the second particle = 4 m/s x 7 s = 28 m
So, the distance at which the two particles meet from the origin is the sum of the distance covered by each particle.
Distance = Distance covered by the first particle + Distance covered by the second particle
Distance = 56 m + 28 m = 84 meters
Therefore, the two particles meet from the origin at a distance of 84 meters.
particle 1
x = -21 + 8 t
particle 2
x = 7 + 4 t
so
-21 + 8 t = 7 + 4 t
4 t = 28
t = 4 seconds
x = 7 + 16 = 23