Calculate the mass of NaOH required to make 500ml of 0.5 M aqueous solution (Molecular mass of NaOH=40)
NaOH mols=0.5*500
NaOH mass required=0.5*500*molecular mass of NaOH
500 mL is HALF a liter. Therefore .5 + 40 = 20 grams
typo: mass required=0.5*(500*10^-3)*40 g
To calculate the mass of NaOH required to make a 0.5 M aqueous solution, you can use the formula:
Mass = Volume × Concentration × Molecular Mass
Here, the volume is given as 500 mL and the concentration is given as 0.5 M. The molecular mass of NaOH is 40 g/mol.
First, convert the volume from milliliters to liters by dividing by 1000:
Volume = 500 mL ÷ 1000 = 0.5 L
Now, substitute the values into the formula:
Mass = 0.5 L × 0.5 M × 40 g/mol
Simplify the calculation:
Mass = 0.5 × 0.5 × 40 g
Mass = 10 g
Therefore, the mass of NaOH required to make a 500 mL of 0.5 M aqueous solution is 10 grams.