A boy is going from one place to another.He goes 100 m north and then 70 m east . Find the displacement of the boy from his starting point.
(100)^2 + (70)^2 = X^2
Solve for X.
To find the displacement of the boy from his starting point, we need to determine the shortest straight-line distance between his initial position and final position.
Let's break down the problem:
- The boy moves 100 m north.
- Next, he moves 70 m east.
We can represent this in terms of a coordinate system, where the starting point is the origin (0,0). Moving 100 m north means reaching a point (0, 100).
Then, moving 70 m east from this point, he ends up at (70, 100).
To calculate the displacement, we use the distance formula based on the coordinates:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the coordinates of the starting point are (0, 0), and the coordinates of the final point are (70, 100):
Distance = √((70 - 0)^2 + (100 - 0)^2)
= √(70^2 + 100^2)
= √(4900 + 10000)
= √14900
≈ 122 m (rounded to the nearest whole number)
Therefore, the displacement of the boy from his starting point is approximately 122 meters.