What is the pressure on a swimmer 10meters below the surface of a lake?
The pressure on an object at a depth in water is given by P= atmospheric pressure + pgh , where p=density of water, h height of liquid column, g= acceleration due to gravity ,1.01×10^5 + 1000 × 9.8× 10~ 2×10^5Ans.
what is the weight of a column of water 1m^2 10 m high?
weight=volume*density*g=10m^3*1E3kg/m^3*9.8N/kg
pressure=weight/area= above/1m^2
= 10*1000*9.8pascal=98kPa
check all that math, then when you figure it is right, remember that 32ft of water (about 10m) is equivalent to one atmosphere (101kpa), and that depth is the column height of a water baromenter....http://practicalphysics.org/water-barometer.html
Annegrace ,you can reply me if you are satisfied with the answer or not. You can message me anytime.I would be very happy if you do so.
To calculate the pressure on a swimmer at a certain depth, we can use the concept of hydrostatic pressure. Hydrostatic pressure is defined as the pressure exerted by a fluid at rest and arises due to the weight of the fluid above.
To calculate this, we use the formula:
Pressure = Density × Gravity × Depth
1. Density: The density of water is approximately 1000 kg/m³.
2. Gravity: The acceleration due to gravity is approximately 9.8 m/s².
3. Depth: Given that the swimmer is 10 meters below the surface.
Now, let's plug in the values into the formula:
Pressure = 1000 kg/m³ × 9.8 m/s² × 10 m
Calculating this will give us the pressure on the swimmer at a depth of 10 meters below the surface of the lake.