The average age of man and his son is 28 years the ratio of their ages 3 : 1 respectively what is the man's age
man's age --- 3x
non' age ---- x
(note 3x : x = 3 : 1)
so (3x + x)/2 = 28
4x = 56
x= 14
finish it up
Please explain
To find the man's age, we can use the given ratio of their ages.
Let's assume the son's age is x.
According to the given ratio, the man's age would be 3x.
The average age of the man and his son is given as 28 years, which means:
(3x + x) / 2 = 28
Combining like terms, we get:
4x / 2 = 28
Simplifying, we find:
2x = 28
Divide both sides of the equation by 2:
x = 14
Therefore, the son's age is 14 years.
To find the man's age, multiply the son's age by 3:
3 * 14 = 42
Thus, the man's age is 42 years.
To find the man's age, we'll start by representing the given information. Let's assume the man's age is M, and his son's age is S.
According to the problem, the average age of the man and his son is 28 years. So, we can set up the equation:
(M + S) / 2 = 28
The ratio of their ages is given as 3:1. This means the man's age (M) is three times the son's age (S). So, we can write another equation:
M = 3S
Now, we have a system of two equations. We can solve this system using substitution or elimination.
Let's solve using substitution:
Substitute M in the first equation with its value in terms of S from the second equation:
(3S + S) / 2 = 28
(4S) / 2 = 28
2S = 28
S = 28 / 2
S = 14
Now, substitute the value of S back into the second equation to find M:
M = 3 * 14
M = 42
Therefore, the man's age is 42 years.