How many moles of oxygen are given by the complete decomposition of 1.225gram of potassium chloride
2KClO3 ==> 2KCl + 3O2
mols KClO3 = 1.225/molar mass KClO3 = ?
mols O2 produced = mols KClO3 x 3/2 = ?
To determine the number of moles of oxygen produced by the complete decomposition of 1.225 grams of potassium chloride (KCl), we need to use the stoichiometry of the reaction.
The balanced chemical equation for the decomposition of potassium chloride is:
2 KCl → 2 K + Cl₂
This equation tells us that for every 2 moles of potassium chloride, we get 1 mole of oxygen.
The molar mass of potassium chloride (KCl) is approximately 74.55 g/mol. Therefore, we can calculate the moles of potassium chloride using the given mass:
Moles of KCl = Mass of KCl / Molar mass of KCl
= 1.225 g / 74.55 g/mol
≈ 0.0164 moles
Since the stoichiometry ratio between KCl and oxygen is 2:1, we can conclude that the number of moles of oxygen produced is also 0.0164 moles.
To determine the number of moles of oxygen produced by the complete decomposition of potassium chloride (KCl), we need to follow these steps:
Step 1: Determine the molar mass of potassium chloride (KCl).
The molar mass of KCl can be calculated by adding the atomic masses of potassium (K) and chlorine (Cl) together. According to the periodic table, the atomic mass of K is 39.10 grams per mole (g/mol), and the atomic mass of Cl is 35.45 g/mol. Adding these masses gives us:
Molar mass of KCl = 39.10 g/mol + 35.45 g/mol = 74.55 g/mol.
Step 2: Convert the given mass of potassium chloride to moles.
We are given that the mass of potassium chloride is 1.225 grams. To convert this mass to moles, we divide it by the molar mass of KCl:
Moles of KCl = Mass of KCl / Molar mass of KCl
Moles of KCl = 1.225 g / 74.55 g/mol = 0.0164 mol.
Step 3: Determine the stoichiometry of the reaction.
To find the number of moles of oxygen produced, we need to know the balanced chemical equation for the decomposition of potassium chloride. The balanced equation is:
2 KCl(s) → 2 K(s) + Cl2(g)
From the balanced equation, we can see that for every 2 moles of KCl, we get 1 mole of Cl2.
Step 4: Calculate the moles of oxygen produced.
Since there is no oxygen in the balanced equation, we cannot determine the moles of oxygen directly from the given mass of potassium chloride.
Therefore, it is not possible to determine the number of moles of oxygen produced by the complete decomposition of 1.225 grams of potassium chloride without further information.