A body of 6 kg rest in limiting equilibrium onan inclined plane whose slope is 30° the plane is raised to a slope of 60 degree the forcw in kg weight around the plane required to support it is
F = M*sin A = 6*sin60 = 5.2 kg.
This is wrong
To find the force required to support the body on the inclined plane, we can use the concept of resolving forces into their components.
Here's how you can calculate the force:
1. Determine the weight of the body: The weight of the body can be calculated using the formula: weight = mass × acceleration due to gravity. In this case, the mass is given as 6 kg, and the acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the body is 6 kg × 9.8 m/s^2 = 58.8 N.
2. Resolve the weight into its components: The weight acting on the inclined plane can be split into two components: one acting perpendicular to the plane (normal force) and the other acting parallel to the plane (force of gravity along the slope).
3. Calculate the perpendicular component (normal force): The perpendicular component is equal to the weight acting perpendicular to the plane. In this case, the inclined plane is at a slope of 30°, so the normal force is given by normal force = weight × cos(angle of inclination). So, the normal force is equal to 58.8 N × cos(30°).
4. Calculate the parallel component (force of gravity along the slope): The parallel component of the weight is equal to the weight acting parallel to the plane. In this case, the inclined plane is at 30°, so the force of gravity along the slope is given by force = weight × sin(angle of inclination). Therefore, the force of gravity along the slope is equal to 58.8 N × sin(30°).
Now, let's calculate the force required when the plane is raised to a slope of 60°:
5. Resolve the weight into its components: Repeat steps 3 and 4 for the new angle of inclination, which is 60°.
6. Calculate the perpendicular component (normal force) for 60°: The normal force is given by normal force = weight × cos(angle of inclination). Therefore, the normal force is equal to 58.8 N × cos(60°).
7. Calculate the parallel component (force of gravity along the slope) for 60°: The force of gravity along the slope is given by force = weight × sin(angle of inclination). Therefore, the force of gravity along the slope is equal to 58.8 N × sin(60°).
By comparing the forces in steps 4 and 7, you can find the change in the force required to support the body when the plane is raised to a slope of 60°.