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how many 0.25-pF capacitors must be connected in parallel in order to store 1.2uC of charge when connected to a battery providing a potential difference of 10v?

  • physics -

    C = q/V
    q = C V
    so each stores 2.5 * 10^-12 C
    so we need 1.2*10^-6/2.5*10^-12 = .48*10^6

  • physics -

    1.2x10^-6 / 0.25x10^-12 = 4.8x10^6

  • 10 volts * C = q -

    but C times ten volts = q per capacitor

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