State a number which is multiply by itself exceeds to hafl century by dozen one
I will try to unravel your garbled language, and get
x^2 = 100/2 + 12+1
If that's not right, maybe you can fix it up. Not quite sure what "dozen one" means.
Let's break down the problem step-by-step:
1. "Multiply by itself": This means we need to find a number that, when multiplied by itself (squared), becomes the desired value.
2. "Exceeds half a century by a dozen one": In this phrase, "half a century" refers to 50, and "a dozen one" refers to adding 11. So, we need to find a number that, when squared, exceeds 50 by 11.
To solve this, we can set up an equation:
Let's assume the number is "x."
According to the problem, x^2 = 50 + 11.
So, x^2 = 61.
To find the value of x, we need to take the square root of both sides of the equation:
√(x^2) = √61
Therefore, the number that satisfies the given condition is the square root of 61.
Answer: The number is √61 (approximately 7.81).
To find the number that, when multiplied by itself, exceeds half a century by a dozen one (13), we can use algebraic reasoning.
Let's assume the unknown number as 'x'.
According to the given information, we can form an equation:
x * x = (50/2) + 13
Simplifying the equation:
x^2 = 25 + 13
x^2 = 38
Now, to find the value of 'x', we need to take the square root of both sides:
√(x^2) = √38
Taking the square root, we get:
x = √38
Therefore, the number that, when multiplied by itself, exceeds half a century by a dozen one is approximately equal to the square root of 38.