How many milliliters of glacial acetic acid are needed to prepare 2.0 L of 10.0% u/v acetic acid?
Well, here's a joke for you: Why did the scarecrow win an award? Because he was outstanding in his field!
Now, back to your question. To find out how many milliliters of glacial acetic acid you would need, we need to do a little math. The concentration is given as 10.0% u/v, which means that for every 100 mL of the solution, there is 10 mL of acetic acid.
We want to make 2.0 L of the solution, which is equivalent to 2000 mL. If we divide that by 100, we get 20. So, we would need 20 times the amount of acetic acid, which is 200 mL of glacial acetic acid.
So, you'll need 200 mL of glacial acetic acid to prepare 2.0 L of 10.0% u/v acetic acid.
To calculate the amount of glacial acetic acid needed, we can use the formula:
(concentration of desired solution * volume of desired solution) / concentration of stock solution
Given:
Concentration of desired solution = 10.0% u/v (10.0 grams per 100 mL)
Volume of desired solution = 2.0 L (2000 mL)
Concentration of stock solution (glacial acetic acid) = 100% u/v (100 grams per 100 mL)
Let's plug in the values into the formula:
(10.0% * 2000 mL) / 100.0% = (10.0 * 2000) / 100 = 20000 / 100 = 200 mL
Therefore, 200 mL of glacial acetic acid is needed to prepare 2.0 L of 10.0% u/v acetic acid.
To calculate the amount of glacial acetic acid needed to prepare 2.0 L of 10.0% u/v acetic acid, we need to consider the definition of "10.0% u/v acetic acid." A 10.0% u/v (weight/volume) solution means that 10.0 grams of acetic acid is dissolved in 100 mL (0.1 L) of solution.
Therefore, the concentration of acetic acid in the 10.0% u/v solution is 10.0 g/0.1 L = 100 g/L.
To find out how many milliliters of glacial acetic acid are needed, we can use the equation:
C₁V₁ = C₂V₂
Where:
C₁ is the initial concentration (in g/L) of glacial acetic acid
V₁ is the initial volume (in L) of glacial acetic acid
C₂ is the final concentration (in g/L) of the 10.0% u/v acetic acid
V₂ is the final volume (in L) of the 10.0% u/v acetic acid
Let's substitute the known values into the equation:
C₁ * V₁ = C₂ * V₂
Since we want to find the volume of glacial acetic acid (V₁), we rearrange the equation to solve for V₁:
V₁ = (C₂ * V₂) / C₁
Now, let's plug in the values:
C₁ = 100 g/L (concentration of glacial acetic acid)
V₂ = 2.0 L (final volume of the 10.0% u/v acetic acid)
C₂ = 10.0 g/L (concentration of the 10.0% u/v acetic acid)
V₁ = (10.0 g/L * 2.0 L) / 100 g/L
V₁ = 0.2 L
Finally, convert the volume to milliliters:
0.2 L * 1000 mL/L = 200 mL
Therefore, 200 milliliters of glacial acetic acid are needed to prepare 2.0 L of 10.0% u/v acetic acid.
I assume you mean w/v.
10% w/v = 10 g Solute/100 mL solvent. So
10 g x (2000 mL/100 mL) = ? g solute.