The sum of the square of a number and one,divided by the difference of 1 from the square gives 221/220.what is the number?
(x^2+1)/(x^2-1) = 221/220
220 x^2 + 220 = 221 x^2 - 221
x^2 = 441
x = sqrt(441) = 21
(x^2+1)/(x^2-1) = 221/220
Thanku
To find the value of the number, let's break down the given information into an equation.
Let's assume the unknown number is "x". According to the problem, we know:
(The sum of the square of a number and one) divided by (the difference of 1 from the square) = 221/220
In equation form, this can be written as:
[(x^2 + 1) / (x^2 - 1)] = 221/220
To solve this equation, we can cross-multiply:
220(x^2 + 1) = 221(x^2 - 1)
Expanding the equation gives:
220x^2 + 220 = 221x^2 - 221
Rearranging the terms gives:
221x^2 - 220x^2 = 221 - 220
x^2 = 1
Taking the square root of both sides, we get:
x = ±1
Therefore, the number can be either 1 or -1.