How much Na2CO3 would you weigh to prepare M/20 Na2CO3 solution in 100cm3 volumetric flask?
20M=(mass/molmassNa2CO3)/.100
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To calculate the amount of Na2CO3 needed to prepare a M/20 Na2CO3 solution in a 100 cm3 volumetric flask, you will need the molar mass of Na2CO3 and the desired concentration of the solution.
Step 1: Determine the molar mass of Na2CO3
Na (Sodium) has a molar mass of 22.99 g/mol
C (Carbon) has a molar mass of 12.01 g/mol
O (Oxygen) has a molar mass of 16.00 g/mol
The molar mass of Na2CO3 is calculated as follows:
2(Na) + 1(C) + 3(O) = (2*22.99) + 12.01 + (3*16.00) = 105.99 g/mol
Step 2: Calculate the amount of Na2CO3 needed
The concentration M/20 implies that there is 1 mole of Na2CO3 in 20 liters of solution.
Since we want to prepare the solution in a 100 cm3 (0.1 liter) volumetric flask, we can use the following conversion factor:
1 mole Na2CO3 / 20 liters = x moles Na2CO3 / 0.1 liters
Rearranging the equation, we have:
x = (1 mole Na2CO3 / 20 liters) * (0.1 liters / 1 mole Na2CO3)
x = 0.005 moles Na2CO3
Step 3: Convert moles to grams
To calculate the mass of Na2CO3 needed, we can use its molar mass:
Mass = moles × molar mass
Mass = 0.005 moles × 105.99 g/mol
Mass = 0.52995 grams
Therefore, you would weigh approximately 0.53 grams of Na2CO3 to prepare a M/20 Na2CO3 solution in a 100 cm3 volumetric flask.