Dennise says that (2x+7)^2=(7-2x)^2.Did you agree with dennised?explain.
at the very least, try using some value for x, say x=1.
Does (2+7)^2 = (7-2)^2 ??
Just answer that directly please Steve
Boy, you're not going to do anything on this, are you?
To determine if Dennise's statement is true, we can expand both sides of the equation and see if they are equal.
Starting with Dennise's equation:
(2x + 7)^2 = (7 - 2x)^2
Expanding the left side of the equation using the binomial theorem:
(2x + 7)^2 = (2x + 7) * (2x + 7)
= (2x)(2x) + (2x)(7) + (7)(2x) + (7)(7)
= 4x^2 + 14x + 14x + 49
= 4x^2 + 28x + 49
Expanding the right side of the equation using the same approach:
(7 - 2x)^2 = (7 - 2x) * (7 - 2x)
= (7)(7) - (7)(2x) - (2x)(7) + (2x)(2x)
= 49 - 14x - 14x + 4x^2
= 4x^2 - 28x + 49
Comparing the expanded forms of the equation, we can see that:
Left side: 4x^2 + 28x + 49
Right side: 4x^2 - 28x + 49
We can observe that the left and right sides of the equation are not the same. The left side has the term 28x, while the right side has the term -28x. Since the equation is not balanced, we can conclude that Dennise's statement is false.