Can anyone balance this equation out of me? Sorry I don't quite understand how to balance equations.

When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coefficients are:

__ bromine trifluoride (g) -----> __ bromine (g) + __ fluorine (g)

2BrF3 -> Br2 + 3F2

To balance the equation __ bromine trifluoride (g) ---> __ bromine (g) + __ fluorine (g), we need to ensure that there are equal numbers of each element on both sides of the equation.

Let's go through the process step-by-step:

1. Start by counting the number of atoms of each element on both sides.

On the left-hand side:
- Bromine: 1
- Fluorine: 3

On the right-hand side:
- Bromine: 1
- Fluorine: 1

2. Since there is an imbalance in the number of fluorine atoms, we need to multiply the number of atoms on the right-hand side by a coefficient to equalize it with the left-hand side.

__ bromine trifluoride (g) ---> __ bromine (g) + __ fluorine (g)

Let's multiply the number of fluorine atoms on the right-hand side by 3:

__ bromine trifluoride (g) ---> __ bromine (g) + 3 fluorine (g)

Now, we have:
On the left-hand side:
- Bromine: 1
- Fluorine: 3

On the right-hand side:
- Bromine: 1
- Fluorine: 3

3. Next, let's balance the bromine atoms. Since there is an equal number of bromine atoms on both sides, we don't need to make any changes.

__ bromine trifluoride (g) ---> __ bromine (g) + 3 fluorine (g)

Now, we have:
On the left-hand side:
- Bromine: 1
- Fluorine: 3

On the right-hand side:
- Bromine: 1
- Fluorine: 3

4. Finally, let's balance the coefficient in front of the bromine trifluoride on the left-hand side. Since there is only one molecule of bromine trifluoride, the coefficient is 1.

1 bromine trifluoride (g) ---> __ bromine (g) + 3 fluorine (g)

Now, we have:
On the left-hand side:
- Bromine: 1
- Fluorine: 3

On the right-hand side:
- Bromine: 1
- Fluorine: 3

Therefore, the balanced equation with the smallest possible integer coefficients is:

1 bromine trifluoride (g) ---> 1 bromine (g) + 3 fluorine (g)

To balance a chemical equation, you need to ensure that the number of each type of atom is the same on both sides of the equation. In this case, you have to balance the equation:

__ bromine trifluoride (g) -----> __ bromine (g) + __ fluorine (g)

To balance this equation, you need to determine the coefficients for each compound or element that will make the number of atoms on the left side equal to the number of atoms on the right side.

Let's start by counting the number of each type of atom on both sides of the equation:

On the left side, we have 1 bromine and 3 fluorine atoms in bromine trifluoride.
On the right side, we have 1 bromine and 1 fluorine atom.

To balance the bromine atoms, we need to put a coefficient of 1 in front of bromine on the right side:

__ bromine trifluoride (g) -----> 1 bromine (g) + __ fluorine (g)

Now let's balance the fluorine atoms:

On the left side, we have 3 fluorine atoms.
On the right side, we have 1 fluorine atom.

To balance the fluorine atoms, we need to put a coefficient of 3 in front of fluorine on the right side:

__ bromine trifluoride (g) -----> 1 bromine (g) + 3 fluorine (g)

Therefore, the balanced equation is:

1 bromine trifluoride (g) -----> 1 bromine (g) + 3 fluorine (g)

The coefficients are 1, 1, and 3 respectively.