An ant climbs up 5 stairs, each of width 20 cm and height 20 cm . Find the distance covered and displacement of ant ?

up one step: x=20cm, y=20cm,

displacement=final position less initial
=sqrt(20²+20²)
=28.28 cm (approx.)

So what is the displacement for 5 steps?

To find the distance covered, we need to find the total length the ant travels while climbing the stairs.

Each step has a width and a height of 20 cm. Since the ant climbs 5 stairs, the total distance covered in climbing the stairs is:

Distance covered = (5 stairs) × (20 cm per stair)
Distance covered = 100 cm

Therefore, the ant covers a distance of 100 cm while climbing the stairs.

Now, let's calculate the displacement of the ant.

Displacement is the straight-line distance from the initial position to the final position. Since the ant climbs up the stairs and reaches a higher position, the displacement is equal to the vertical height it climbed.

The height of each stair is given as 20 cm, and the ant climbs 5 stairs, so the displacement of the ant is:

Displacement = (5 stairs) × (20 cm per stair)
Displacement = 100 cm

Therefore, the displacement of the ant is 100 cm, which is equal to the total vertical height it climbed while climbing the stairs.

To solve this problem, we'll need to calculate the distance covered and displacement separately.

To find the distance covered, we'll first calculate the total horizontal distance traveled by the ant.

Distance = number of steps * width of each step
Distance = 5 steps * 20 cm
Distance = 100 cm

The ant covers a total distance of 100 cm horizontally.

To find the vertical distance traveled by the ant, we'll calculate the total height climbed.

Height climbed = number of steps * height of each step
Height climbed = 5 steps * 20 cm
Height climbed = 100 cm

Now, to calculate the displacement, we'll use Pythagoras theorem. The displacement is the shortest straight-line distance from the starting point to the ending point.

Displacement = square root of (Horizontal distance^2 + Vertical distance^2)
Displacement = square root of (100 cm^2 + 100 cm^2)
Displacement = square root of (10000 cm^2 + 10000 cm^2)
Displacement = square root of (20000 cm^2)
Displacement ≈ 141.42 cm

So, the ant covers a distance of 100 cm horizontally and has a displacement of approximately 141.42 cm from its starting point.