(need help with checking answers)
The height , h, in feet, of a bottle rocket is modeled by: h = -16t^2 + 60t
where t is the time in seconds.
A. Factor the expression.
H = 16t^2 +60 = 4(4t^2 + 15)
B. What is the height of the rocket after 2 seconds?
H = 4(4 times 2^2 + 15) = 4(16 + 15) = 128 ft
C. What is the height of the rocket after 3.75 seconds? Explain the solution.
4(4 times 3.75^2 + 15)
H(3.75) = 285
h = -16t^2 + 60t = 4t(-4t+15)
now work on B and C again.
To check the answer for part C, we can substitute the value of t = 3.75 into the given expression for h.
h = -16t^2 + 60t
Substituting t = 3.75, we get:
h(3.75) = -16(3.75)^2 + 60(3.75)
Calculating this expression:
h(3.75) = -16(14.06) + 225
h(3.75) = -224.96 + 225
h(3.75) = 0.04
Therefore, the height of the rocket after 3.75 seconds is approximately 0.04 feet.