On a salmon farm, pool A contains 310 salmon and a second pool B contains 90 salmon. The number of salmon in pool A is decreasing by 15 salmon per month. The number of salmon in pool B is increasing by 15 salmon per month.
After how many months will there be equal number of salmon in each pool?
After x months they will be equal if
310-15x = 90+15x
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To find out after how many months there will be an equal number of salmon in each pool, you need to set up an equation and solve for the number of months.
Let's assume the number of months is represented by 'x'.
In pool A, the number of salmon is initially 310. Over time, the number of salmon decreases by 15 per month. So we can express the number of salmon in pool A at any given month as 310 - 15x.
In pool B, the number of salmon is initially 90. Over time, the number of salmon increases by 15 per month. So we can express the number of salmon in pool B at any given month as 90 + 15x.
To determine when the two pools will have an equal number of salmon, we can set up the following equation:
310 - 15x = 90 + 15x
Let's solve this equation:
310 - 15x = 90 + 15x
Subtract 90 from both sides:
220 - 15x = 15x
Add 15x to both sides:
220 = 30x
Divide both sides by 30:
x = 7.33
Since the number of months cannot be a fraction, we can round up the value of x to the nearest whole number.
Therefore, it will take approximately 8 months for there to be an equal number of salmon in each pool.