An iron vise falls from rest at a great height. Neglecting air resistance, what is its speed after it has fallen for 5 seconds?
v = at
To determine the speed of the iron vise after it has fallen for 5 seconds, we can use the equation for the motion of a falling object:
v = u + gt
Where:
v is the final velocity
u is the initial velocity (which is 0, since the vise starts from rest)
g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
t is the time duration (5 seconds in this case)
Plugging the values into the equation:
v = 0 + (9.8 m/s^2) * 5 s
v = 49 m/s
Therefore, the speed of the iron vise after falling for 5 seconds, neglecting air resistance, is 49 m/s.