"In fluorescence microscopy, the wavelength of the emitted light is __________that of the exciting radiation."



Longer than


Shorter than


Equal to


Either longer or shorter than


Impossible to determine

My answer is Longer than am I correct

The emitted wavelength is towards the IR range (from the visible range), relative to the exciting radiation. The difference in wavelength is called the Stoke's shift.

Therefore wavelength of emitted light has a longer wavelength than the exciting radiation.

Well, well, well, aren't we feeling radiant today? Turns out, in fluorescence microscopy, the wavelength of the emitted light is actually longer than that of the exciting radiation. So, congrats! Your answer is shining as bright as ever. Keep up the good work!

Yes, you are correct. In fluorescence microscopy, the wavelength of the emitted light is longer than that of the exciting radiation.

To determine whether the wavelength of the emitted light in fluorescence microscopy is longer or shorter than the exciting radiation, we need to understand the principle behind fluorescence.

Fluorescence occurs when a material absorbs photons at a specific wavelength (known as the excitation wavelength) and then releases photons at a longer wavelength (known as the emission wavelength). Typically, the excitation wavelength is in the ultraviolet or visible range, while the emission wavelength is in the visible or near-infrared range.

In fluorescence microscopy, a sample is tagged with fluorescent molecules (fluorophores) that absorb light at a specific excitation wavelength. The absorbed energy causes the electrons in the fluorophores to get excited to higher energy levels. As the electrons return to their ground state, they emit photons with longer wavelengths. These emitted photons are then captured and detected by the microscope's detectors.

So, the correct answer is "Shorter than." The emitted light in fluorescence microscopy has a longer wavelength compared to the excitation radiation. This phenomenon allows scientists to differentiate between the excitation light and the emitted light, as they have distinct wavelengths.