how many liters of distilled water must be added to 80 liters of 60% acid solution to obtain a 50 % acid solution?

80 L of 60% acid contains

(80*0.60)=48 L of 100% acid.
To make 50% acid, it must be diluted to have a total volume of 48/(0.5)=96 L.

Leave it to you to figure out how much distilled water to be added.

To solve this problem, we need to calculate how much distilled water needs to be added to the 80 liters of 60% acid solution to achieve a 50% acid solution. Here is the step-by-step solution:

Step 1: Start with the given information.
- Initial volume of acid solution = 80 liters.
- Concentration of acid in the solution = 60%.
- Final desired concentration of acid = 50%.

Step 2: Calculate the amount of acid in the initial solution.
- Amount of acid in 80 liters of 60% acid solution = 80 liters * 60% = 48 liters.

Step 3: Set up an equation to determine the final volume of the solution.
Let "V" be the volume of distilled water to be added.
- Amount of acid in the final solution = 48 liters.
- Amount of acid in the final solution = 50% * (80 liters + V liters).

Step 4: Solve the equation for "V".
- 48 liters = 0.5 * (80 liters + V liters).
- 48 liters = 40 liters + 0.5V liters.

Step 5: Simplify and solve for "V".
- 48 liters - 40 liters = 0.5V liters.
- 8 liters = 0.5V liters.
- V = 8 liters / 0.5.
- V = 16 liters.

Therefore, 16 liters of distilled water must be added to the 80 liters of 60% acid solution to obtain a 50% acid solution.

To solve this problem, we need to determine how much distilled water should be added to the 80 liters of 60% acid solution to obtain a 50% acid solution. Here's a step-by-step explanation of the process:

Let's assume that x liters of distilled water should be added.

The amount of acid present in the 80 liters of 60% acid solution is given by:
Amount of acid in 80 liters = 80 * (60/100) = 48 liters

After adding x liters of distilled water, the total volume of the mixture will be:
Mixture volume = 80 + x liters

The amount of acid present in the mixture can be expressed as:
Amount of acid in the mixture = 50% of (80 + x) liters = (50/100) * (80 + x) = (80 + x)/2 liters

Since the amount of acid in the mixture should be equal to 48 liters, we can set up the equation:
(80 + x)/2 = 48

To solve for x, we can start by multiplying both sides of the equation by 2:
80 + x = 96

Next, we subtract 80 from both sides of the equation:
x = 96 - 80

Simplifying, we get:
x = 16

Therefore, 16 liters of distilled water must be added to the 80 liters of 60% acid solution to obtain a 50% acid solution.

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