Math
posted by Kms .
In Exercises 16–18, use the following information. At a college, 43% of the students are women, 15% of the students are art majors, 4% have not chosen a major, and 8% are women and art majors. A faculty member conducts an experiment and selects students at random to participate.
16. What is the probability that a randomly selected student will be either a woman or an art major?
Would this one be 43/70 + 15/70  8/70 = 5/7
Or would the denominator be 100 and equal 1/2

43/100 women
15/100 art
take away the 8/100 that are both
yes I get 1/2 
Bless you

You are welcome. I think they left out the 38 percent who majored in physics :)
(To get 70% you counted the 8 twice, I think really the total is 62 but they gave percent, not number of students so it is out of 100 )
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