The average daily minimum temperature for Pablo’s hometown can be modeled by the function f(x)=15.3sin(πx6)+44.1 , where f(x) is the temperature in °F and x is the month.
x = 0 corresponds to January.
What is the average daily minimum temperature in June?
Round to the nearest tenth of a degree if needed.
Use 3.14 for π .
yes im aware of posting twice is against rules but my last post im sure no one will see my response. i am still stuck on solving this if anyone could help me that would be great!!
It's more perhaps you did not read the last response from a helper.
http://www.jiskha.com/display.cgi?id=1496930282
Also, please show details of your previous answer, so we can better help you with your difficulties.
To find the average daily minimum temperature in June, we need to substitute the value of x for June in the given function.
Since x = 0 corresponds to January, x = 6 corresponds to June.
We can plug in x = 6 into the function f(x) = 15.3sin(πx/6) + 44.1 and calculate the result.
f(6) = 15.3sin(π(6)/6) + 44.1
First, simplify π/6 to 3.14/6 = 0.5233 (rounded to four decimal places).
f(6) = 15.3sin(0.5233) + 44.1
Now, calculate sin(0.5233) using a calculator:
sin(0.5233) ≈ 0.4999 (rounded to four decimal places).
f(6) = 15.3 * 0.4999 + 44.1
Next, multiply:
f(6) ≈ 7.64047 + 44.1
Finally, add:
f(6) ≈ 51.74047
Therefore, the average daily minimum temperature in June, rounded to the nearest tenth of a degree, is approximately 51.7°F.
To find the average daily minimum temperature in June, we need to substitute the value corresponding to June into the given function.
In the function f(x) = 15.3sin(πx/6) + 44.1, x represents the month. Since x = 0 corresponds to January, we need to figure out which month corresponds to x = 5 (June).
To do that, we need to consider the fact that January is the first month, and June is the sixth month. This means that there are five months between January and June.
So, when x = 5, we can substitute it into the function:
f(5) = 15.3sin(π(5)/6) + 44.1
Now, simplify the expression using 3.14 for π:
f(5) = 15.3sin((3.14 * 5)/6) + 44.1
f(5) = 15.3sin((15.7)/6) + 44.1
Using a calculator to find the sine value:
f(5) ≈ 15.3sin(2.617) + 44.1
f(5) ≈ 15.3 * 0.429 + 44.1
f(5) ≈ 6.578 + 44.1
f(5) ≈ 50.678
Therefore, the average daily minimum temperature in June, rounded to the nearest tenth, is approximately 50.7°F.