Lead(3) nitrate decomposes to form three products owygen lead(2) oxide and nitrogen dioxide (balance)
As far as I know there is no lead(III) nitrate.There is a lead(II) nitrate.
2Pb(NO3)2 ==> 2PbO + O2 + 4NO2
To balance the chemical equation for the decomposition of lead(II) nitrate (Pb(NO3)2), we need to make sure that we have the same number of each type of atom on both sides of the equation. Here's how you can balance the equation step by step:
1. Write down the unbalanced equation:
Pb(NO3)2 → PbO + NO2 + O2
2. Start by balancing the elements other than oxygen and nitrogen. In this case, we have lead (Pb) and nitrogen (N):
Pb(NO3)2 → PbO + 2NO2 + O2
By adding a coefficient of 2 in front of NO2, we balance the nitrogen atoms.
3. Now, let's balance the oxygen atoms. On the product side, we have 2 oxygen atoms from PbO and 4 oxygen atoms from NO2, totaling 6 oxygen atoms. On the reactant side, we only have 3 oxygen atoms from Pb(NO3)2.
To balance the oxygen, we need to add a coefficient of 3/2 in front of O2:
Pb(NO3)2 → PbO + 2NO2 + (3/2)O2
However, we can't have fractional coefficients in a balanced chemical equation. To remove the fraction, let's multiply the entire equation by 2:
2Pb(NO3)2 → 2PbO + 4NO2 + 3O2
This gives us an integer coefficient for O2.
4. Finally, let's check if all the elements are balanced. After balancing the equation, we have:
2Pb(NO3)2 → 2PbO + 4NO2 + 3O2
On both sides, we have 2 lead (Pb) atoms, 6 nitrogen (N) atoms, and 12 oxygen (O) atoms. Therefore, the equation is balanced.
The balanced equation for the decomposition of lead(II) nitrate is:
2Pb(NO3)2 → 2PbO + 4NO2 + 3O2