You roll a number cube twice. Find P(even, then not 2). Write the probability as a fraction in simplest form. Explain your answer. Please help!
not me and my grandma tryin find these answers ✋
This is a two step experiment where each step is independent of the other. The probability of both succeed is the product of the probability of each step. [called the product rule]
Step 1:
P(even)=P({2,4,6} out of {1,2,3,4,5,6})=3/6
P(2)=P({2} out of {1,2,3,4,5,6})=1/6
Now use the product rule to find the probability of both events happening (success), simplify the fraction as requested.
Note: in general, it is preferable to use fractions for probability problems because answers are exact. Using the calculator will give inaccurate or ambiguous results due to round off errors.
It said NOT 2; therefore, the product of 1/2 times 5/6 would be your answer
ummm is anyone going to answer my question from literally 2017? My little sister needs help but I dont know how to explain to her.
so 5/12?
i need a simplifyed answer for this cause im stupid
can you please explain?
You're still not a good person if you call people a loser.
Srsly?? We still haven't answered this question from 2017?!??
I apologize for the delay in answering your question. Here is the solution to your problem:
To find the probability of rolling an even number on the first roll and not rolling a 2 on the second roll, we need to find the probability of each event happening separately and then multiply them.
The probability of rolling an even number on the first roll is 3/6 (since there are three even numbers in a six-sided die). The probability of not rolling a 2 on the second roll is 5/6 (since there are five numbers that are not 2 in a six-sided die).
Therefore, the probability of rolling an even number on the first roll and not rolling a 2 on the second roll is:
P(even, then not 2) = P(even) × P(not 2) = (3/6) × (5/6) = 15/36 = 5/12
So the probability of rolling an even number on the first roll and not rolling a 2 on the second roll is 5/12.