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Find the largest no that divides 630 and 940 leaving reminders 6 and 4 respectively
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did this for you last night.
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Find the largest no that divides 630 and 940 leaving reminders 6 and 4 respectively
Top answer:
630 = 2^4•3•13+6 940 = 2^3•3^2•13+4 so, your number is 2^3•3•13 = 312 630 = 2*312+6 940
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Find the largest number which divides 630 and 940 leaving remainder 6 and 4 respectively
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simple method: numbers which divide by 630 leaving remainder of 6: 636 1266 1896 2526 3156 3786 4416
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find the largest number that divides 615 and 963 leaving remainder 6 in each case.
Top answer:
Dear Anamika To get the largest number (HCF) 1st subtract 6 from 615 and 963 615 - 6 = 609 963 - 6 =
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find the largest number which divides 245 and 1029 Leaving remainder 5 in each case
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To find the largest number that divides 245 and 1029, leaving a remainder of 5 in each case, we can
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What is the largest number that divides 1206 and 321 leaving remainder
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let the largest no. be y 1206/y=6 1206=6y y=1206/6 y=201 similarly 321/y=6 6y=321 y=321/6 y=53.5
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Find the greatest number which divides 2011 and 2623 , leaving remainders 9 and 5 respectively
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Student Life
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Find the largest integer N for which N−6 evenly divides N^3−6.
Top answer:
N^3−6 is zero Modulo (N-6). If we compute Modulo (N-6) then obviously: N-6 = 0 -----> N = 6 Here
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k is the greatest number that divides 2996, 4752 and 7825 leaving the remainder in each case equal. Find the product of the
Top answer:
no idea what are "the marks of K"
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Find the largest number which divides 62 132 237 to leave the same reminder
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To find the largest number that divides all three numbers (62, 132, and 237) and leaves the same
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Q.1)Find hcf and lcm of the following using fundamntal theorem of arithematic
12,720 and 540. Q.2)Find the greatest number which
Top answer:
A.1) To find the HCF and LCM of 12, 720, and 540 using the Fundamental Theorem of Arithmetic, we
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630=
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630=
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