find the coordinates of the points where l cuts the axes.
line equation l is 5+y-2x=0
Write down your equation on a piece of paper.
To find the x-intercept, let y = 0
(put your little pinkie finger over the y term blocking it out to look at )
5-2x=0
in your head you can see that x = 5/2
do the same to get the y-intercept
To find the coordinates where the line cuts the axes, we need to find the points where the line intersects the x-axis and the y-axis separately.
To find the point where the line intersects the x-axis (y-coordinate is 0), we substitute y = 0 into the equation of the line and solve for x:
5 + 0 - 2x = 0
-2x = -5
x = -5 / -2
x = 5/2 or 2.5
So, the point where the line intersects the x-axis is (2.5, 0).
To find the point where the line intersects the y-axis (x-coordinate is 0), we substitute x = 0 into the equation of the line and solve for y:
5 + y - 2(0) = 0
5 + y = 0
y = -5
So, the point where the line intersects the y-axis is (0, -5).
Therefore, the coordinates of the points where the line cuts the axes are (2.5, 0) and (0, -5).
To find the coordinates of the points where the line cuts the axes, we need to determine the points where the line intersects the x-axis and the y-axis.
To find the point where the line intersects the x-axis, we set y = 0 and solve for x.
5 + 0 - 2x = 0
-2x = -5
x = -5 / -2
x = 2.5
So, the point where the line intersects the x-axis is (2.5, 0).
To find the point where the line intersects the y-axis, we set x = 0 and solve for y.
5 + y - 2 * 0 = 0
5 + y = 0
y = -5
So, the point where the line intersects the y-axis is (0, -5).
Therefore, the coordinates of the points where the line cuts the axes are (2.5, 0) and (0, -5).