Find moles of O atoms in 9.00g of Mg(NO3)2.
0.36
mols Mg(NO3)2 = grams/molar mass = ?
Then you know that 1 mol Mg(NO3)2 contains 6 mols O atoms.
0.3
Moles of O atom in 9.00 of Mg (NO3)2
To find the moles of oxygen atoms in a given amount of Mg(NO3)2, we need to follow these steps:
Step 1: Determine the molar mass of Mg(NO3)2:
The molar mass of an element is the mass of one mole of that element. To find the molar mass of Mg(NO3)2, we need to consider the atomic masses of magnesium (Mg), nitrogen (N), and oxygen (O), as well as the number of atoms of each element in the formula.
Molar mass of Mg (atomic mass) = 24.31 g/mol
Molar mass of N (atomic mass) = 14.01 g/mol
Molar mass of O (atomic mass) = 16.00 g/mol
Mg(NO3)2 has one magnesium atom (Mg) with a mass of 24.31 g/mol and two nitrate ions (NO3), each containing one nitrogen atom (N) and three oxygen atoms (O).
So, the molar mass of Mg(NO3)2 can be calculated as follows:
Molar mass of Mg(NO3)2 = (24.31 g/mol) + 2 * [(14.01 g/mol) + 3 * (16.00 g/mol)] = 148.31 g/mol
Step 2: Calculate the number of moles of Mg(NO3)2:
We can use the formula:
Number of moles = Mass / Molar mass
In this case, the mass of Mg(NO3)2 is given as 9.00 g, so:
Number of moles of Mg(NO3)2 = 9.00 g / 148.31 g/mol
Step 3: Determine the number of moles of oxygen atoms:
To find the number of moles of oxygen atoms in Mg(NO3)2, we need to consider that each mole of Mg(NO3)2 contains two nitrate ions (NO3), and each nitrate ion contains three oxygen atoms (O).
So, the number of moles of oxygen atoms is calculated as follows:
Number of moles of oxygen atoms = Number of moles of Mg(NO3)2 * 2 * 3
Now, you can substitute the calculated value of moles of Mg(NO3)2 from step 2 into the equation:
Number of moles of oxygen atoms = (9.00 g / 148.31 g/mol) * 2 * 3
Simplify the expression:
Number of moles of oxygen atoms = (9.00 g / 148.31 g/mol) * 6
Finally, calculate the value:
Number of moles of oxygen atoms ≈ 0.364 mol
Therefore, there are approximately 0.364 moles of oxygen atoms in 9.00g of Mg(NO3)2.