Which of these will contain avogadro number of molecules:
1)22.4dm3 of co2 at 27∘c and 1atm contain
2)44g of at 27∘c and 1 atm
3)2.7dm3 of co2 at 546k and 2atm
4)11.2l of co2 at 273 and 2atm
start by recalling that 1 mole occupies 22.4L (dm^3) at STP
Then use the fact that
PV=kT
since all the items are given in the same units, the formula works just fine. Just find the one which matches the standard values.
1 mol contains Avogadro's number. So use PV = nRT and calculate which is 1 mol.
To determine which of these options contains Avogadro's number of molecules, we need to calculate the number of molecules in each option.
1) 22.4 dm3 of CO2 at 27∘C and 1 atm:
To calculate the number of molecules, we can use the ideal gas equation, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
From the equation, we can rearrange it to solve for n (number of moles):
n = PV / RT
Given:
P = 1 atm
V = 22.4 dm3
R = 0.0821 L·atm/(mol·K) (gas constant)
T = 27 + 273 = 300 K (convert Celsius to Kelvin)
Substituting these values into the equation, we have:
n = (1 atm) * (22.4 dm3) / (0.0821 L·atm/(mol·K) * 300 K)
n ≈ 1 mol
Since 1 mole contains Avogadro's number of molecules (approximately 6.022 x 10^23), option 1 contains Avogadro's number of molecules.
2) 44 g of A at 27∘C and 1 atm:
To calculate the number of molecules, we need to determine the number of moles using the molar mass of A.
Given:
Mass of A = 44 g (grams)
Molar mass of A = x g/mol
To find the molar mass of A, we need more information to determine the chemical formula or the specific element or compound being referred to.
3) 2.7 dm3 of CO2 at 546 K and 2 atm:
We can use the same formula as in option 1 to calculate the number of moles.
Given:
P = 2 atm
V = 2.7 dm3
R = 0.0821 L·atm/(mol·K) (gas constant)
T = 546 K
n = (2 atm) * (2.7 dm3) / (0.0821 L·atm/(mol·K) * 546 K)
n ≈ 0.217 mol
Since option 3 contains less than 1 mole, it does not contain Avogadro's number of molecules.
4) 11.2 L of CO2 at 273 K and 2 atm:
Again, we can use the same formula to calculate the number of moles.
Given:
P = 2 atm
V = 11.2 L
R = 0.0821 L·atm/(mol·K) (gas constant)
T = 273 K
n = (2 atm) * (11.2 L) / (0.0821 L·atm/(mol·K) * 273 K)
n ≈ 0.945 mol
Since option 4 contains less than 1 mole, it does not contain Avogadro's number of molecules.
To summarize, option 1 (22.4 dm3 of CO2 at 27∘C and 1 atm) contains Avogadro's number of molecules.