For a =( 2 ÷3)and b=(-1÷4)..Find

a).. a+b

b).. | a+b |

c).. Find the length of the vector i + 2j-- 2k

this is calculus. Surely you can work with fractions...

(a) a+b = (2/3)+(-1/4) = 8/12-3/12 = 5/12

(b) what do you think?

recall that the length of ai+bj+ck = √(a^2+b^2+c^2)