If a coin is tossed and a number cube is rolled, what is the probability that the coin shows heads and the number cube shows 3?
I got 1/12
The choices are 1/12, 1/2,1/9,1/6, I tried everything and I'm not really sure about my answer.
(1/2) * (1/6) = 1/12
You're right.
ur right the probability of the coin 3/6 (1/2) times the probability of the cube 1/6 = 3/6 x 1/6 = 3/36 which simplifies to 1/12
Ok Thank You!!
You're welcome.
To find the probability of two independent events occurring, you need to multiply their individual probabilities.
First, let's determine the probability of the coin showing heads. The coin has two equally likely outcomes - heads or tails. Since it is a fair coin, the probability of heads is 1/2.
Now, let's determine the probability of the number cube showing a 3. A standard number cube has six equally likely outcomes - the numbers 1, 2, 3, 4, 5, and 6. Since each outcome is equally likely, the probability of rolling a 3 is 1/6.
To find the probability of both events occurring, multiply the individual probabilities: (1/2) x (1/6) = 1/12.
Therefore, your answer of 1/12 is correct.