solve y=0.04x^2+8.3x+4.3
What is the quadratic equation?
To solve the equation y = 0.04x^2 + 8.3x + 4.3, we first need to rearrange the equation to the standard quadratic form, which is ax^2 + bx + c = 0.
The equation given is already in the standard quadratic form, so we can proceed to solve it using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 0.04, b = 8.3, and c = 4.3.
Now we can substitute these values into the quadratic formula:
x = (-8.3 ± √(8.3^2 - 4 * 0.04 * 4.3)) / (2 * 0.04)
Simplifying further:
x = (-8.3 ± √(68.89 - 8.64)) / (0.08)
x = (-8.3 ± √(60.25)) / 0.08
x = (-8.3 ± 7.77) / 0.08
This gives us two solutions for x:
x1 = (-8.3 + 7.77) / 0.08 ≈ 5.38
x2 = (-8.3 - 7.77) / 0.08 ≈ -20.64
Therefore, the solutions to the equation y = 0.04x^2 + 8.3x + 4.3 are approximately x = 5.38 and x = -20.64.