To what volume should 1.19 ml of an 8.00 m acetic acid solution be diluted in order to obtain a final solution that is 1.50 M?
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Ahhhhh, someone else posting from her phone and not checking what auto-correct does.
Do you mean molarity? Or molality? You need to be more careful before you hit that submit button!
I don't know about the morality of these answers but I'll try. First, I assume your 8.00 m actually is 8.00 M. m means molality. M means molarity. Use the dilution formula of
mL1 x M1 = mL2 x M2
1.19 x 8.00 = mL2 x 1.50
Solve for mL2. Post your work if you get stuck.
575
Well, isn't this just an acid-emic question! Let's break it down step by step, with a dash of humor!
First, let's determine the initial number of moles of acetic acid in the 1.19 ml solution. To do that, we need to convert milliliters to liters by dividing it by 1000:
1.19 ml ÷ 1000 = 0.00119 L
Next, let's calculate the initial number of moles of acetic acid:
moles = concentration × volume
0.00119 L × 8.00 M = 0.00952 moles of acetic acid
Now, let's find out how many moles of acetic acid we need in the final solution, which is 1.50 M. We'll use the same formula:
moles = concentration × volume
0.00952 moles = 1.50 M × volume
Now, it's time for some algebraic fun! Let's solve for the volume:
volume = 0.00952 moles ÷ 1.50 M
volume = 0.00635 L = 6.35 ml
So, if you dilute 1.19 ml of 8.00 M acetic acid solution to a final volume of 6.35 ml, you'll end up with a 1.50 M solution. Just don't stir it too vigorously or you might cause an acid wave!
To determine the volume to which the 1.19 ml of the 8.00 M acetic acid solution should be diluted, we can use the equation for dilution:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
In this case, we know:
C1 = 8.00 M
V1 = 1.19 ml
C2 = 1.50 M
V2 = ?
Rearranging the equation, we have:
V2 = (C1V1) / C2
Substituting the given values:
V2 = (8.00 M * 1.19 ml) / 1.50 M
Now we need to convert the volume from milliliters to liters, as the concentration is given in moles per liter:
V2 = (8.00 M * 0.00119 L) / 1.50 M
Simplifying the equation:
V2 = 0.00952 L / 1.50 M
Dividing the volume by the concentration:
V2 = 0.00635 L
Finally, to convert the volume back to milliliters:
V2 = 0.00635 L * 1000 ml/L
V2 ≈ 6.35 ml
Therefore, to obtain a final solution with a concentration of 1.50 M, the 1.19 ml of the 8.00 M acetic acid solution should be diluted to approximately 6.35 ml.
mo·ral·i·ty
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principles concerning the distinction between right and wrong or good and bad behavior.
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