In Aunt Melly’s attics there are also spiders and ants, the total of 136 legs and 20 heads. If a spider has 8 legs and an ant has 6 legs, how many spiders and how many ants are there?
s + a = 20 , where s is the number of spiders and a is the number of ants.
8s+6a = 136
you have two equations in 2 unknowns, just solve for s and a
hint: I would use substitution using s = 20-a
56
So aunt melly but your nephew, YNW Melly, has a murder on his mind and is in jail.
Btw, YNW Melly is a rapper, look him up.
signed by- XXXTENTACION
Each ant has 6 legs. How many legs do 3 ants have?
Ants 1 2 3
Legs 6 ?
A.
6
B.
12
C.
16
D.
18
To solve this problem, we need to set up a system of equations representing the information given. Let's assume the number of spiders is denoted by s and the number of ants is denoted by a.
First, we can set up an equation for the total number of legs:
8s + 6a = 136
We can also set up an equation for the total number of heads:
s + a = 20
Now we have a system of two equations with two variables. We can solve this system to find the values of s and a.
To do this, we can use the method of substitution or elimination. Let's use the substitution method in this case.
From the second equation, we get:
s = 20 - a
Now we can substitute this expression for s into the first equation:
8(20 - a) + 6a = 136
Now simplify and solve for a:
160 - 8a + 6a = 136
-2a = -24
a = 12
Plug this value of a back into the second equation:
s + 12 = 20
s = 8
So there are 8 spiders and 12 ants in Aunt Melly's attic.