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Find Solution set of underrootx=6x.here under root x means positive square root of x.

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    sqrt (x) = 6 x

    x = 36 x^2 but may introduce false solution along with correct one

    36 x^2 -x = 0

    x(36 x -1) = 0

    x = 0 or x = 1/36

    x = 0 works, 0 = 0

    if x = 1/36
    1/6 = 6/36 yes that also works

    so x = 0 or x = 1/36

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