Find Solution set of underrootx=6x.here under root x means positive square root of x.
sqrt (x) = 6 x
x = 36 x^2 but may introduce false solution along with correct one
36 x^2 -x = 0
x(36 x -1) = 0
x = 0 or x = 1/36
x = 0 works, 0 = 0
if x = 1/36
1/6 = 6/36 yes that also works
so x = 0 or x = 1/36