If total of 9 students appear in exam.in how many ways results be announced?

To determine the number of ways the results can be announced for 9 students, we can use the concept of permutations.

Permutations refer to the arrangement of objects in a particular order. In this case, we need to find the number of ways the results can be announced, which means we are arranging the students' results.

Since all 9 students appeared for the exam, we need to find arrangements for all 9 students.

The formula to calculate permutations is given by:
P(n,r) = n! / (n-r)!

Where:
P(n,r) represents the number of permutations of n objects taken r at a time,
! represents the factorial (product of all positive integers less than or equal to the given number),
n represents the total number of objects,
r represents the number of objects taken at a time.

In our case, we need to find the number of ways the results can be announced for all 9 students, which means r = n. Therefore, the formula becomes:
P(9,9) = 9! / (9-9)!

Calculating this expression:
P(9,9) = 9! / 0!
P(9,9) = 9! / 1

Now, let's compute the factorial:
9! = 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
9! = 362,880

Substituting this value back into the formula:
P(9,9) = 362,880 / 1 = 362,880

Hence, the results can be announced in 362,880 different ways.